2021.10.27 统计7的倍数或包含7的数字

Question

【每日一题】2021.10.27

求100以内的正整数是7的倍数或包含7的数字并统计总个数。

编程语言：包括但不限于Python

Answer 1

public class Number {
    public static void main(String[] args) {
        int num = 0;
        for (int i = 1; i <= 100; i++) {
            int ge = i % 10;//把个位数算出来
            int shi = i / 10 % 10;//把十位数算出来
            if (ge == 7 || shi == 7) {
                num++;
                System.out.print(" " + i);
            } else if (i % 7 == 0) {
                num++;
                System.out.print(" " + i);
            }
        }
        System.out.println();
        System.out.println("总个数：" + num);
    }
}

运行结果：

Answer 2

int count = 0;
for (int i = 1; i <= 100; i++)
{
if (i % 7 == 0 || i.ToString().Contains("7"))
{
count ++;
}
}

Answer 3

a=[]
num=0
for i in range(1,101):
if i%7==0 or i%10==7:
a.append(i)
num+=1
print('总个数:',num)
print(a)