请问这个报错怎么回事

Question

请问这个报错怎么回事，该怎么解决？

代码如下

#include <stdio.h>
#include <stdlib.h>
#include <windows.h>

int main () {
    int one, two, three, four, six, sever, eight, nine, ten;

    scanf("%d", &one);
    for ( one <= 99999999 ) {
        if (one > 9999999) {
            two = one / 10000000;
        } else {
            two = 0;
        }
        if (one > 999999) {

            three = one / 1000000 % 10;
        } else {
            three = 0;
        }
        if (one > 99999) {

            four = one / 100000 % 10;
        } else {
            four = 0;
        }
        if (one > 9999) {

            six = one / 10000 % 10;
        } else {
            six = 0;
        }
        if (one > 999) {
            sever = one / 1000 % 10;
        } else {
            sever = 0;
        }
        if (one > 99) {

            eight = one / 100 % 10;
        } else {
            eight = 0;
        }
        if (one > 9) {

            nine = one / 10 % 10;
        } else {
            nine = 0;
        }
        ten = one % 10;
        printf("%d", two + three + four + six + sever + eight + nine + ten);
        break;
    }
    system("pause");

    return 0;
}

Answer 1

应该是for循环格式不对吧
试试for(;one<=99999999;)
for循环的一般形式为
for (表达式1; 表达式2; 表达式3)
{
语句;
}