这个二维列表到底该怎么处理？

Question

data=[['*','G01','G02','G03','G04','G05'],
['1','0','2','3',4','3']
['2','3','6','5','3','8']]

请问上面这个数组怎么样在不用库的情况下变成：
data=[['*','1','2'],['G01','0','3'],['G02',2','6'],['G03','3','5'],['G04','4','3'],['G05','3','8']]
也就取列，但是行个数不确定，列个数不确定，只知道每行的个数相等，所以没办法用数字索引。

Answer 1

data=[['*','G01','G02','G03','G04','G05'],
      ['1','0','2','3','4','3'],
      ['2','3','6','5','3','8']]

print(list(map(list, zip(*data))))