servlet 如何渠道jquery ajax 中Select的值
function f() {
new Ajax.Request("servlet/GetProvinceServlet", {
method : "post",
onSuccess : function(req) {
var provinces = req.responseText.evalJSON();
for (i = 0; i < provinces.length; i++) {
var province = provinces[i];
var op1 = new Option(province.name, i);
$('s1').options[i] = op1;
}
f1();
}
});
}
function getXmlHttpRequest() {
var xmlHttpRequest = null;
if ((typeof XMLHttpRequest) != 'undefined') {
xmlHttpRequest = new XMLHttpRequest();
} else {
xmlHttpRequest = new ActiveXObject('Microsoft.XMLHttp');
}
return xmlHttpRequest;
}
function f1() {
var xmlReq = getXmlHttpRequest();
var url = "servlet/GetCityServlet";
xmlReq.open("post", url, true);
xmlReq.setRequestHeader("Content-Type",
"application/x-www-form-urlencoded");
xmlReq.onreadystatechange = function() {//匿名函数
if (xmlReq.readyState == 4) {//服务器响应已经完成
//alert(xmlReq.status);
if (xmlReq.status == 200) {//如果服务器返回的是错误信息
var citys = xmlReq.responseText.evalJSON();//获得数据
$('s2').innerHTML = '';//清空第二个下拉列表中的类容
for (i = 0; i < citys.length; i++) {
var city = citys[i];
var op1 = new Option(city.name, i);
$('s2').options[i] = op1;
}
} else {
alert("error");
}
}
};
xmlReq.send("prvince=" + $("s1").value);
}
1092617065
2019/04/05 00:33- java
- json
- ajax
- javascript
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