如何判断二维列表和字典？

Question

data=[['G05', 'Hopscotch', 'N', '2'],['G07', 'Dominoes', 'S', '5'],['G08', 'Chess', 'N', '3'],['G10','Monopoly', 'N', '3'],['G02', 'MineCraft', 'S', '5']]

data1={'G07': [3, 2], 'G08': [2, 2], 'G10': [1, 1],'G02': [5, 3],'G05': [5, 3]}

请问该怎么在不使用库的情况下，判断二维列表里面每个表的第一个值和字典的键是否相等？如果相等则将键的值追加到列表后面？
变成这样
[['G05', 'Hopscotch', 'N', '2','5','3'],['G07', 'Dominoes', 'S', '5','3','2'],['G08', 'Chess', 'N', '3','2','2'],['G10','Monopoly', 'N', '3','1','1'],[G02', 'MineCraft', 'S', '5','5','3']]
二维列表和字典的顺序不确定

Answer 1

keys = data1.keys()
for d in data:
if d[0] in keys:
d += data1[d[0]]

print(data)