将结构体传入函数是发生的错误

Question

代码如下：

#include<stdio.h>
#include<windows.h>
void printS(struct Nerbor *nerbor);
void printS(struct Nerbor *nerbor)
{
    printf("%ld %s %d",nerbor->number,nerbor->human.name,nerbor->human.year);
    printf("%ld %s %d",(nerbor+1)->number,(nerbor+1)->human.name,(nerbor+1)->human.year);
}
struct Nerbor 
{
    long number;
    struct Human human;
};

struct Human
{
    char name[10];
    int year;
}human;



int main(void)
{
    struct Nerbor *him;
    struct Nerbor nerbor[2] = {{302039823,{"John",1985}},{302039776,{"Alice",2000}}};
    him = &nerbor[0];
    printS(him);
    system("pause");
    return 0;
}

报错如下：
invalid use of incomplete type 'struct Nerbor'；
应输入标识符；
field 'human' has incomplete type 'Human'；

Answer 1

#include<stdio.h>
#include<windows.h>
struct Human
{
    char name[10];
    int year;
}human;

struct Nerbor 
{
    long number;
    struct Human human;
};
void printS(struct Nerbor *nerbor);
void printS(struct Nerbor *nerbor)
{
    printf("%ld %s %d",nerbor->number,nerbor->human.name,nerbor->human.year);
    printf("%ld %s %d",(nerbor+1)->number,(nerbor+1)->human.name,(nerbor+1)->human.year);
}
int main(void)
{
    struct Nerbor *him;
    struct Nerbor nerbor[2] = {{302039823,{"John",1985}},{302039776,{"Alice",2000}}};
    him = &nerbor[0];
    printS(him);
    system("pause");
    return 0;
}

Answer 2

请问这个函数的放置位置是有什么讲究吗

Answer 3

在函数或者数据结构被调用之前必须已经有声明或者实现

Answer 4

好的谢谢