编写一个将C语言变成 MIPS 汇编程序

Question

望各位帮忙看看，现在就想要答案，蟹蟹各位潜水专家，感谢解答，感谢回答，感谢解答。编写一个 MIPS 汇编程序，相当于这个 C 程序：在原有的基础上完成这个程序。我需要答案，我想要的是直接把代码告诉我

//  read a line from stdin and and then an integer n
//  Print the character in the nth-position

#include <stdio.h>

// line of input stored here
char line[256];

int main(void) {

    printf("Enter a line of input: ");
    fgets(line, 256, stdin);

    printf("Enter a position: ");
    int n;
    scanf("%d", &n);

    printf("Character is: ");
    printf("%c", line[n]);
    printf("%c", '\n');

    return 0;
}

#  read a line from stdin and and then an integer n
#  Print the character in the nth-position

# n in $t0

main:
    la   $a0, str0       # printf("Enter a line of input: ");
    li   $v0, 4
    syscall

    la   $a0, line       # fgets(buffer, 256, stdin)
    la   $a1, 256
    li   $v0, 8
    syscall

    la   $a0, str1       # printf("Enter a position: ");
    li   $v0, 4
    syscall

    li   $v0, 5          # scanf("%d");
    syscall
    move $t0, $v0

    la   $a0, str2       # printf("Character is: ");
    li   $v0, 4
    syscall


    li   $a0, '?'        # printf("%c", '?');
    li   $v0, 11
    syscall


    li   $a0, '\n'       # printf("%c", '\n');
    li   $v0, 11
    syscall

    li   $v0, 0          # return 0
    jr   $ra

.data
str0:
    .asciiz "Enter a line of input: "
str1:
    .asciiz "Enter a position: "
str2:
    .asciiz "Character is: "


# line of input stored here
line:
    .space 256

Answer 1

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