c语言求解简单的四则运算表达式if else

Question

Answer 1

#include<stdio.h>
 
int main()
{
    float a;
    float c;
    char b;
    
    scanf("%f%c%f",&a,&b,&c);
    
    if(b=='+')
        printf("%.2f\n",a+c);
    else if(b=='-')
        printf("%.2f\n",a-c);
    else if(b=='*')
        printf("%.2f\n",a*c);
    else if(b=='/')
    {
        if(c!=0.)
            printf("%.2f\n",a/c);
        else
            printf("除数为零\n");
    }else{
        printf("%Error!");
    }
    
    return 0;
}