表达式放在printf中和拿出来为什么结果不同呢？

Question

#include <stdio.h>
void f(double num);

int main(void){
double num;
scanf("%lf",&num);
f(num);
}

void f(double num){
int k = (int) (num/10);
printf("k=%d\n",k);
int m=(num/10-k)*10;
printf( "m=%d\n",m);
printf( "表达式=%d",((num/10-k)*10));
}

Answer 1

这边建议多巩固基本类型，printf( "表达式=%d",((num/10-k)*10));这个表达式结果是double类型。%d->%lf再试试