js函数生成正则表达式遇到问题

Question

  function reg(str) {
            var regStr = ``;
            var num = 0;
            var temp = '';
            var arr = []
            for (var i = 0; i < str.length; i++) {
                if (str.charAt(i) != '.' && str.charAt(i) != '/' && str.charAt(i) != '-') {
                 
                    console.log('普通' + str.charAt(i));
 
 
                    console.log("111--" + temp)
 
 
num++;
temp = num;
                    
                } else {
                
                    arr.push(temp)
                    num = 0;
 
                    // console.log("2222--" + temp)
 
                    console.log('符号' + str.charAt(i));
                    regStr += `\d{${temp}}`
                    regStr += str.charAt(i)
 
                    if (str.charAt(i) == '/') {
                        regStr += `\d{${temp}}`
}
 
 
}
 
 
}
            console.log(arr)
            return regStr
}
        console.log(reg('xxx.xxx.xxx/xx'))
        console.log(reg('xx.xxx.xxx/xxxx-xx'))
 

预期应该是
'xxx.xxx.xxx/xx' => /\d{3}.\d{3}.\d{3}/\d{2}/
'xx.xxx.xxx/xxxx-xx' => /\d{2}.\d{3}.\d{3}/\d{4}-\d{2}/
不知道为什么最后两个字符串一直生成不出来

Answer 1

给你改了一下，你看看

function reg(str) {
            var regStr = ``;
            var num = 0;
            var temp = '';
            var arr = []
            for (var i = 0; i < str.length; i++) {
                if (str.charAt(i) != '.' && str.charAt(i) != '/' && str.charAt(i) != '-') {
                    num++;           
                } else {
                    regStr += `\d{${num}}`
                    regStr += str.charAt(i)
                    num = 0;
                }
            }
            regStr += `\d{${num}}`
            return regStr
        }
        console.log(reg('xxx.xxx.xxx/xx'))
        console.log(reg('xx.xxx.xxx/xxxx-xx'))

 觉得有用的话采纳一下哈