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- 技术专家团-Joel 2021-11-05 12:59关注
你好同学,这就是考察对旋转图形的理解,一般用比如xy平面的一个圆,然后绕着y轴旋转,就得到了环
x0 = 3; y0=1; r0 = 1; theta1 = linspace(0,2*pi, 20); theta2 = linspace(0,2*pi, 100); [T1, T2] = meshgrid(theta1, theta2); X = (r0*cos(T1)+x0).*cos(T2); Y = r0*sin(T1); Z = (r0*cos(T1)+x0).*sin(T2); figure(2);clf h = mesh(X,Y,Z); hold on h1 = mesh(Y,X,Z+x0+r0); shading flat;axis equal off; view(15,45); set(h,'facecolor','r','edgecolor','none') set(h1,'facecolor','g','edgecolor','none') light('position',[0,0,20],'style','local','color','w');lighting phong; light('position',[-20,0,0],'style','local','color','w');lighting phong;
然后画自己认为喜欢的图形
figure; s=1000; I=ones(s,s,3); w=2.2; for h=1:s for k=1:s z=((k-s/2)-i*(h-30-s/2))*w/s; for r=1:6 z=z^5-0.65*i-0.0001/z^5+0.0001; end r=real(z); a=0.0001*r^2; I(h,k,1)=min(0.9,-4*r+a); I(h,k,2)=min(0.9,-r+a); I(h,k,3)=min(1,3*r+a); end end imshow(I)
答题不易如有帮助还望题主给个宝贵的采纳支持一下答主答题哟谢谢啦(づ ̄3 ̄)づ╭❤~
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