python循环结构中的相关编程

Question

Answer 1

lst=list(map(int,input().split()))
positive=negative=s=ave=cnt=0
for i in lst:
    if i>0:
        positive += 1
    elif i<0:
        negative += 1
    s+=i
    cnt+=1
ave = s/cnt 
print(positive,negative,s,'%.2f' % ave,sep='\n')