下面图片中的这个内容要怎么做，该如何去解决它呢

Question

请教下面图片中的这个内容该怎么做呢，我能该如何去解决这种问题呢？

Answer 1

/**
 * struct Point {
 *    int x;
 *    int y;
 * };
 */

class Solution {
public:
    float calculate_gradient(struct Point &point_x ,struct Point &point_y)
    {
        if(point_x.x-point_y.x != 0)
            return (float)(point_x.y-point_y.y)/(float)(point_x.x-point_y.x);
        else
            return 1000.f;
    }
    /**
     * 
     * @param points Point类vector 
     * @return int整型
     */
    int maxPoints(vector<Point>& points) {
        int max_points=0;
        int temp_max_points=0;
        float gradient=0.f;
        if(points.size() == 0)
            return 0;
        if(points.size()==1)
            return 1;
        
        for(int i=0;i<points.size();++i)
        {
            for(int j=i+1;j<points.size();++j)
            {
                temp_max_points=2;
                gradient = calculate_gradient(points.at(i) ,points.at(j));
                for(int k=0;k<points.size();++k)
                {
                    if(k==i || k==j) continue;
                    if( (0 == memcmp(&points.at(k),&points.at(i),sizeof(struct Point))) || 
                        (0 == memcmp(&points.at(k),&points.at(j),sizeof(struct Point))))
                    {
                        ++temp_max_points;
                        continue;
                    }
                    if(gradient == 1000.f)
                    {
                        if(points.at(i).x-points.at(k).x == 0)
                            ++temp_max_points;
                    }else{
                        if((points.at(i).x-points.at(k).x)!=0 && gradient == calculate_gradient(points.at(i) ,points.at(k)))
                            ++temp_max_points;
                    }
                }
                if(temp_max_points>max_points)
                    max_points = temp_max_points;
            }
        }
        return max_points;
    }
};