C++ 统计一行英文中的单词个数 碰到标点符号还有很长的空格怎么办 怎样能让碰到很多空格按一格来算

Question

Answer 1

#include<iostream>
#include <string> 
using namespace std;
bool isEnglish(char ch) {
    int n = (int)ch;
    return (n >= (int)'a' && n <= (int)'z') || (n >= (int)'A' && n <= (int)'Z');
}
int main() {
    string s;
    while (getline(cin, s)) {
        int i = 0, len = s.length();
        int workSpace = 0, count = 0;
        char ch;
        for (i = 0; i < len; i++) {
            ch = s.at(i);
            if (!workSpace && isEnglish(ch)) {
                count += 1;
                workSpace = 1;
            }
            else if (workSpace && !isEnglish(ch) && ch != '-') {
                workSpace = 0;
            }
        }
        cout << count << endl;
    }
}
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