不是已经重写了compareTo的方法吗为什么还会报错

Question

package java;

import java.util.Arrays;

public class goods implements Comparable {
    private  String name ;
    private double price;

    public goods(String name, double price) {
        this.name = name;
        this.price = price;
    }

    public goods() {
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public double getPrice() {
        return price;
    }

    public void setPrice(double price) {
        this.price = price;
    }

    @Override
    public int compareTo(Object o) {
        if(o instanceof goods){
            goods good=(goods) o;
            if(this.price>good.price){
                return 1;
            }
            else if(this.price< good.price){
                return -1;
            }else{
                return 0;
            }
        }
        throw new RuntimeException("gg");
    }

    public static void main(String[] args) {
        goods arr[]=new goods[4];
        arr[0]=new goods("lng",2);
        arr[1]=new goods("leng",24);
        arr[2]=new goods("lg",21);
        arr[3]=new goods("l",234);
        Arrays.sort(arr);
        System.out.println(Arrays.toString(arr));

    }
}

不是已经重写了compareTo的方法吗为什么还会报错，不能比较类的大小。

Answer 1

 List<Goods> list=new ArrayList<>();
    Goods good1=new Goods("a",2);
    Goods good2=new Goods("b",24);
    Goods good3=new Goods("c",21);
    Goods good4=new Goods("d",224);
    list.add(good1);
    list.add(good2);
    list.add(good3);
    list.add(good4);

mian方法里面可以这么写