我想要按照我第一个界面
按照顺序换行4行
public class person implements Serializable {
private String username;
private String user_password;
private String user_email;
private String user_phonenumber;
public void setUsername(String name){
this.username = name;
}
public String getUsername() { return username;
}
public String getUser_password() {
return user_password;
}
public void setUser_password(String user_password) {
this.user_password = user_password;
}
public String getUser_email() {
return user_email;
}
public void setUser_email(String user_email) {
this.user_email = user_email;
}
public String getUser_phonenumber() {
return user_phonenumber;
}
public void setUser_phonenumber(String user_phonenumber) {
this.user_phonenumber = user_phonenumber;
}
<TextView
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:textColor="#ff00ff"
android:id="@+id/tv_userInfor"
android:textSize="20dp"
android:textStyle="bold"
/>
public void onClick(View v) {
//从文本框中获取用户名,存入到strname中
String strname = edt_name.getText().toString();
if (strname.length() < 3 || strname.length() > 20)
edt_name.setError("请输入正确的用户名,用户名 在3-20个字符之间");
String password = edt_password.getText().toString();//获取第一次密码
if (password.equals("") || password.equals("")) {
edt_password.setError("密码不能为空");
} else if (password.equals(password)) {
Toast.makeText(this, "注册成功", Toast.LENGTH_LONG).show();
person Person = new person();
Person.setUsername(edt_name.getText().toString());
Person.setUser_phonenumber(edt_phonenumber.getText().toString());
Person.setUser_email(edt_email.getText().toString());
Person.setUser_password(edt_password.getText().toString());
Intent intent = new Intent(this, UserActivity.class);
intent.putExtra("userinfor", Person);
startActivity(intent);
}