关于简单的四则运算，求解

Question

Answer 1

#include <stdio.h>
int main()
{
    int n,i,a,b;
    double t;
    scanf("%d",&n);
    for(i=0;i<n;i++)
    {
        scanf("%d %d",&a,&b);
        printf("%d ",a+b);
        printf("%d ",a*b);
        printf("%d ",a-b);
        if(b != 0)
        {
            t = a*1.0/b;
            if(t == (int)t)
                printf("%d\n",(int)t);
            else
                printf("%.2f\n",t);
        }
    }
    return 0;
}