c/c++n个数两两配对不重复

Question

求助！如果随机匹配n个数，要实现两两配对，若共有奇数个数则随机选一个数来配对两个数。的代码_(:з」∠)_

Answer 1

你题目的解答代码如下：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
    int n=9, i, j, x,y;
    int a[n];
    int b[n];
    srand((unsigned)time(NULL));
    for( i=0; i<n; i++ )
    {
        a[i] = i+1; //这里直接赋值1到9了，也可以改成 scanf("%d", &a[i]); 读取用户输入
        b[i] = 0;
    }
    for( i=0; i<n/2; i++ )
    {
        do{
            x = rand() % n;
        } while (b[x]);
        b[x] = 1;
        do{
            y = rand() % n;
        } while (b[y]);
        b[y] = 1;
        printf("%d %d\n", a[x],a[y]);
    }
    if (n%2==1)
    {
        for (x = 0; b[x]; x++) { }
        b[x] = 1;
        do{
            y = rand() % n;
        } while (y==x);
        b[y] = 1;
        printf("%d %d\n", a[x],a[y]);
    }
    return 0;
}

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