为什么这个循环进不去 不服来辩

Question

#include<stdio.h>
#include<math.h>
double n=0,t=1,i=1,n1;
void main()
{
    while((1/i)<pow(10,-6))
    {
        n += n + (1 / i) * t;
        t = -1 * t;
        i += 2;
    }
    printf("%.6f", (4 * n));
}

Answer 1

1 < 0.000001?