关于#java#的问题：为以下操作提供 public方法:●两个 Complex数相加:实部与实部相加,虚部与虚部相加●两个 Complex数相减:实部与实部相减,虚部与虚部相减

Question

创建一个
omplexNumber
类做复数运算,复数具有如下格式:
real+imaginary*i。其中,i为-1的平方根。提供一个构造函数,以
便在此声明此类的对象时,对其进行初始化。为以下操作提供 public
方法:
●两个 Complex数相加:实部与实部相加,虚部与虚部相加
●两个 Complex数相减:实部与实部相减,虚部与虚部相减

Answer 1

class ComplexNumber{
    private double real;
    private double imaginary;
    public ComplexNumber(){ }
    public ComplexNumber(double real,double imaginary){
        this.real = real;
        this.imaginary = imaginary;
    }

    public ComplexNumber add(ComplexNumber b){
        ComplexNumber c = new ComplexNumber();
        c.real = this.real + b.real;
        c.imaginary = this.imaginary + b.imaginary;
        return  c;
    }
    public ComplexNumber subtract(ComplexNumber b){
        ComplexNumber c = new ComplexNumber();
        c.real = this.real - b.real;
        c.imaginary = this.imaginary - b.imaginary;
        return  c;
    }
    public void show(){
        System.out.print(this.real);
        if(this.imaginary>=0)
            System.out.print("+");
        System.out.print(this.imaginary+"i\n");
    }
}
public class TestMain
{
    public static void main(String[] args) {
        ComplexNumber a = new ComplexNumber(1.1,2.5);
        System.out.print("a=");
        a.show();
        ComplexNumber b = new ComplexNumber(2.1,-1.5);
        System.out.print("b=");
        b.show();
        System.out.print("相加：");
        ComplexNumber c = a.add(b);
        c.show();
        System.out.print("相减：");
        ComplexNumber d = a.subtract(b);
        d.show();
    }
}