C语言编程问题求解答

Question

Answer 1

#include<stdio.h>
#include<math.h>
int main() {
    double a, b, c, d, x1, x2;
    scanf("%lf %lf %lf", &a, &b, &c);
    d =  b * b - 4 * a * c;
    if(d == 0) {
        x1 = (-b) / (2 * a);
        printf("x1=x2=%.5lf", x1);
    } else if(d > 0) {
        x1 = (-b + sqrt(d)) / (2 * a);
        x2 = (-b - sqrt(d)) / (2 * a);
        printf("x1=%.5lf;x2=%.5lf", x1,x2);
    } else {
        printf("no solution");
    }
    return 0;
}