那个看看第三题如何做，python题

Question

Answer 1

def Deplace(s):
    res = re.sub(r'(\d+)', '【】', s)
    num = re.findall(r'(\d+)', string)
    for n in num:
        res = re.sub('【】', '【'+n+'】', res, count=1)
    return res

>>> string = '2018 Amazon Jeff Bezos 1120'
>>> Deplace(string)
'【2018】 Amazon Jeff Bezos 【1120】'
>>> string = 'abc 2018 Amazon 678 Jeff 9111Bezos 1120'
>>> Deplace(string)
'abc 【2018】 Amazon 【678】 Jeff 【9111】Bezos 【1120】'
>>>