编程介的小学生 2019-04-19 23:24 采纳率: 20.5%
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超大数字的精确的计算的问题,如何运用C语言的程序的设计的形式实现这个算法

Problem Description
Everyone knows that the letter “E” is the most frequent letter in the English language. In fact, there are one hundred sixteen E’s on this very page ... no, make that one hundred twenty one. Indeed, when spelling out integers it is interesting to see which ones do NOT use the letter “E”. For example 6030 (six thousand thirty) doesn’t. Nor does 4002064 (four million two thousand sixty four).
It turns out that 6030 is the 64th positive integer that does not use an “E” when spelled out and
4002064 is the 838th such number. Your job is to find the n-th such number.
Note: 1,001,001,001,001,001,001,001,001,000 is “one octillion, one septillion, one sextillion, one quintil-lion, one quadrillion, one trillion, one billion, one million, one thousand”. (Whew!)

Input
The input file will consist of multiple test cases. Each input case will consist of one positive integer n (less than 231) on a line. A 0 indicates end-of-input. (There will be no commas in the input.)

Output
For each input n you will print, with appropriate commas, the n-th positive integer whose spelling does not use an “E”. You may assume that all answers are less than 1028.

Sample Input
1
10
838
0

Sample Output
2
44
4,002,064

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