求解猜数游戏用循环结构

Question

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
    int x, n, i, count;
    char ch;
    srand((unsigned)time(NULL));
    do {
        n = rand() %100+1;
        for (i = 1; i <= 10; i++)
        {
            printf("请输入一个数字： ");
            scanf("%d", &x);
            if (x > n)
                printf("你输入的数字太大 \n");
            else if (x < n)
                printf("你输入的数字太小 \n");
            else
            {
                printf("恭喜你！猜对了，共猜了%d次\n",i);
                break;
            }
        }
        if (i>10)
            printf("猜了10次未猜对，停止本次猜数\n");

        printf("是否继续（y/n）:");
        scanf("%1s", &ch);
    } while (ch=='y'||ch=='Y');
    return 0;
}

如有帮助，望采纳！谢谢!