编写一个C语言程序，用给定的字符串替换文件中的目标字符串，并显示输出替换的个数。

Question

若文件为：
There are moments in life when you miss someone so much that you just want to pick them from your dreams and hug them for real!

样例输入：
you they
样例输出：
3
There are moments in life when they miss someone so much that they just want to pick them from theyr dreams and hug them for real!

请各位大佬看一下这个有什么比较简便的方法来解决吗？（C语言）

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAXSIZE 300
int str_replace(char * str1, char * str2, char * str3);

int main(){
    char str1[MAXSIZE];
    char str2[MAXSIZE];
    char str3[MAXSIZE];
    gets(str1);
    scanf("%s %s",&str2,&str3);
    int num=str_replace(str1, str2, str3);
    printf("%d\n",num);
    printf("%s\n",str1);
    return 0;
}

int str_replace(char * str1, char * str2, char * str3){
    int i, j, k, done, count = 0, gap = 0,num=0;
    char temp[MAXSIZE];
    for(i = 0; i < strlen(str1); i += gap){
        if(str1[i] == str2[0]){
            done = 0;
            for(j = i, k = 0; k < strlen(str2); j++, k++){
                if(str1[j] != str2[k]){
                    done = 1;
                    gap = k;
                    break;
                }
            }
            if(done == 0){
                num++;
                for(j = i + strlen(str2), k = 0; j < strlen(str1); j++, k++){ 
                    temp[k] = str1[j];
                }
                temp[k] = '\0'; 
                for(j = i, k = 0; k < strlen(str3); j++, k++){ 
                    str1[j] = str3[k];
                    count++;
                }
                for(k = 0; k < strlen(temp); j++, k++){ 
                    str1[j] = temp[k];
                }
                str1[j] = '\0'; 
                gap = strlen(str2);
            }
        }else{
            gap = 1;
        }
    }
    if(count == 0){
        printf("Can't find the replaced string!\n");
    }
    return num;
}