PTA上的身份证查验问题

Question

pta 第一个测试过不去，还请指点一下。

```c++
#include<iostream>
#include<string>
using namespace std;
int main()
{
    string arry[100];
    int sum,N;
    bool pl = true;
    char m;
    cin >> N;
    for(int i=0;i<N;i++)
         cin >> arry[i];
    for (int i = 0; i < N; i++)
        for(int j=0;j<17;j++)
            if (arry[i][j]> 57 || arry[i][j]< 48)
            {
                if (pl == false)            cout << endl;
                cout << arry[i]; arry[i][1] = '\0'; pl = false; break;
            }
    for(int i=0;i<N;i++)
    if (arry[i][1]!='\0')
    {
        sum = (arry[i][0]-'0') *7 + (arry[i][1] - '0') *9 + (arry[i][2] - '0') *10 + (arry[i][3] - '0') *5 + (arry[i][4] - '0') *8 + (arry[i][5] - '0') *4 + (arry[i][6] - '0') *2 + (arry[i][7] - '0') *1+ (arry[i][8] - '0') *6 + (arry[i][9] - '0') *3 + (arry[i][10] - '0') *7 + (arry[i][11] - '0') *9 + (arry[i][12] - '0') * 10+ (arry[i][13] - '0') *5 + (arry[i][14] - '0') *8 + (arry[i][15] - '0') *4 + (arry[i][16] - '0') *2;
        sum%=11;
        switch (sum)
        {
        case 0:m = '1'; break;
        case 1:m = '0'; break;
        case 2:m = 'X'; break;
        case 3:m = '9'; break;
        case 4:m = '8'; break;
        case 5:m = '7'; break;
        case 6:m = '6'; break;
        case 7:m = '5'; break;
        case 8:m = '4'; break;
        case 9:m = '3'; break;
        case 10:m = '2'; break;
        }
        if (arry[i][17] != m)
        {
            if (pl == false)   cout << endl;
            cout << arry[i];  pl = false;
        }
    }
    if(pl)
    {
        cout << "All passed";
    }
    return 0;
}

Answer 1

将所有pl的地方加上打印，看是到哪里变成false