这个程序是如何输出的？

Question

int a[10] = {0,1,2,3,4,5,6,7,8,9}, *p = a+3;
printf("%d", p[2]);
return 0;
}

Answer 1

*p = a+3; 就代表指针p指向了a[3] p=a[3]

p[2]=p+2=a[3]+2=a[5]