l = [{"Task": "true", "People": "John"}, {'name': '123'}] for item in l: x = item x['z'] = x.pop('name') print(x)
请问如果我想要达到如果该字典中没有name值则continue,如果有则替换key值为z,该怎么写?就是if ( ): continue括号里的写法查不到类似的,恳请赐教
收起
字典取值还有一个get(key)方法,如果key存在则返回value,不存在则放回None,写成代码的话可以这样子写
l = [{"Task": "true", "People": "John"}, {'name': '123'}] for i in l: if i.get('name'): # 不存在就下一次循环 coutinue # 存在则先pop移出name和其所对应的值,并返回给n n = i.pop('name') i['z'] = n
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