let arr1 = [
{fpcid: "2da37fdfe66140089dc3367b21cc6194", fpcNameCode: "34"},
{fpcid: "2da37fdfe66140089dc3367b21cc6195", fpcNameCode: "33"},
{fpcid: "2da37fdfe66140089dc3367b21cc6196", fpcNameCode: "35"},
{fpcid: "2da37fdfe66140089dc3367b21cc6197", fpcNameCode: "36"}
];
let arr2 = [
{fpcid: "2da37fdfe66140089dc3367b21cc6194", fpcNameCode: "34"},
{fpcid: "2da37fdfe66140089dc3367b21cc6195", fpcNameCode: "33"}
];
JS求两个对象数组的差集
[
{fpcid: "2da37fdfe66140089dc3367b21cc6196", fpcNameCode: "35"},
{fpcid: "2da37fdfe66140089dc3367b21cc6197", fpcNameCode: "36"}
]
JS求两个对象数组的差集
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3条回答 默认 最新
- it_lin_web 2019-04-29 09:57关注
let arr1 = [ {fpcid: "2da37fdfe66140089dc3367b21cc6194", fpcNameCode: "34"}, {fpcid: "2da37fdfe66140089dc3367b21cc6195", fpcNameCode: "33"}, {fpcid: "2da37fdfe66140089dc3367b21cc6196", fpcNameCode: "35"}, {fpcid: "2da37fdfe66140089dc3367b21cc6197", fpcNameCode: "36"} ]; let arr2 = [ {fpcid: "2da37fdfe66140089dc3367b21cc6194", fpcNameCode: "34"}, {fpcid: "2da37fdfe66140089dc3367b21cc6195", fpcNameCode: "33"} ]; function fn(arr1,arr2){ let maxArr=arr1.length>arr2.length?arr1:arr2 let minArr=arr1.length>arr2.length?arr2:arr1 let newArr=[] for (let i=0;i<maxArr.length;i++){ var num=0 for(let j=0;j<minArr.length;j++){ if(maxArr[i].fpcid==minArr[j].fpcid || maxArr[i].fpcNameCode==minArr[j].fpcNameCode){ num++ break } } if(num==0){ newArr.push(maxArr[i]) } } return newArr } console.log(fn(arr1,arr2))
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