编写函数对URL进行处理 "http://www.xxx.com/?name=bf&age=23&from=baidu" ,想办法获取url的参数信息(?后边) 包装成对象{name:'bf',age:23,form:'baidu'}
var obj = {};
var arr = [];
var str = `http://www.xxx.com/?name=bf&age=23&from=baidu`;
var k = str.split('?');
var l = k[1].split('&')
var z = [];
console.log(k);
console.log(l);
// 拆分数组 把数组l拆了
for (var i = 0; i < l.length; i++) {
z[i] = l[i].split('=');
}
// 数组z是双数组
for (var j = 0; j < z.length; j++) {
for (var p = 0; p < z[j].length; p++) {
console.log(z[j][p]);
}
// obj.cunchu = z[j][p];
}
console.log(obj);