求错误，求中位数，python代码

Question

L.sort()
i=len(L)

if i%2==0:
    z=L[int(i/2)]+L[int((i/2)-1)]
    if z%2==0:
        print(z/2)
    else:
        print("%.1f"%(z/2))
if i%2!=0:
    z=L[int((i+1)/2)]
    print(z)

Answer 1

试试这个代码

L.sort()
if len(L)%2 != 0:
    print(L[len(L)//2])
else:
    a = L[int((len(L)-1)/2)]
    b = L[int((len(L)+1)/2)]
    print ((a+b)/2)