gdb 中的 watch 命令不管用，不打印新旧值

Question

问题遇到的现象和发生背景

windows子系统下ubuntu20.04, 使用gdb中的watch命令时，程序不中断，也不打印新旧值。

问题相关代码，请勿粘贴截图

这是源码

```c
 1 #include <stdio.h>
  2 #include <stdlib.h>
  3
  4 int main()
  5 {
  6         int i, j, k;
  7
  8         i = 0;
  9         j = 1;
 10         k = 2;
 11
 12         i = j + k;
 13         j = j * k;
 14         k = k * j;
 15
 16         printf("i = %d\n",i);
 17         printf("j = %d\n",j);
 18         printf("k = %d\n",k);
 19
 20         return 0;
 21 }

这是gdb

For help, type "help".
Type "apropos word" to search for commands related to "word"...
Reading symbols from test...
(gdb) b 8
Breakpoint 1 at 0x1155: file test.c, line 8.
(gdb) r
Starting program: /home/lingling/test

Breakpoint 1, main () at test.c:8
8               i = 0;
(gdb) p i
$1 = 32767
(gdb) watch i
Hardware watchpoint 2: i
(gdb) c
Continuing.
i = 3
j = 2
k = 4

Watchpoint 2 deleted because the program has left the block in
which its expression is valid.
__libc_start_main (main=0x8001149 <main>, argc=1, argv=0x7ffffffee468, init=<optimized out>, fini=<optimized out>,
    rtld_fini=<optimized out>, stack_end=0x7ffffffee458) at ../csu/libc-start.c:342
342     ../csu/libc-start.c: No such file or directory.
(gdb) q

###### 运行结果及报错内容 
正常说，continuing之后，应该打印旧值和新值


###### 我的解答思路和尝试过的方法 

###### 我想要达到的结果
按理说应该输出
 Old value=
 New value=

Answer 1

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