Python 對字串進行切割

Question

求該題目程式碼

(1)首先，輸入一串不超過50字元的字串(不得有空格)及一正整數K，兩者以一個空格為間隔
(2)去除字串間非英文字母的字元，例如the$sky@iS!soBlue 應轉換成theskyiSsoBlue
(3)再對字串做大小寫的互相轉換，例如theskyiSsoBlue 應轉換成 THESKYIsSObLUE
(4)對字串以每隔K個字元進行切割，最後一組若字元數不足K則無視
例如：當K=3時，THESKYIsSObLUE 應切割成THE、SKY、IsS、ObL、UE共計5組字串
(5)將每組切割好的字串進行順序反轉後，並以【/】作為間隔輸出。
例如：THE、SKY、IsS、ObL、UE應轉換並輸出UE/ObL/IsS/SKY/THE
==============
Sample input 1:
abcda 1

Sample output 1:
A/D/C/B/A
==============
Sample input 2:
abcDefgHiaaA 2

Sample output 2:
Aa/IA/Gh/EF/Cd/AB
==============
Sample input 3:
mynameisBig5666hehe 10

Sample output 3:
GHEHE/MYNAMEISbI
==============
Sample input 4:
iHaveAnApple 15

Sample output 4:
IhAVEaNaPPLE
==============
Sample input 5:
@H#hHhhhh12*4%H287 3

Sample output 5:
Hh/HHH/hHh

Answer 1

def analyse():
    data = input()
    datalist = data.split(' ')

    res = ''
    for i in datalist[0]:
        if (i>='a' and i<='z'):
            res += i.upper()
        elif  (i>='A' and i<='Z'):
            res += i.lower()
        else:
            pass

    # 分割
    res2 = []
    idnex = int(datalist[1])
    tmp = ''
    c = 0
    for i in res:
        if c % idnex == 0 and not c == 0:
            res2.append(tmp)
            tmp = i
        else:
            tmp += i
        c += 1
    res2.append(tmp)

    #
    res3 = res2.reverse()
    data3 = '/'.join(res2)
    print(data3)

analyse()