c语言vs2019 请问这个代码里的c6385警告怎么解决？

Question

#include<stdio.h>
#define N 100
//中位数
int main()
{
double a[N] = { 0 }, temp;
int i, n = 0, k, j;
while (scanf_s("%lf", &a[n++]) != EOF)
if (getchar() == '\n') break;
for (i = 0; i < n-1; i++)
{
k = i;
for (j = i + 1; j < n; j++)
{
if (a[j] < a[k]) k = j;
if (a[k] != a[i])
{
temp = a[k];
a[k] = a[i];
a[i] = temp;
}
}
}
k = n / 2;
if (n % 2)
printf("%.1lf\n", a[k] );
else
printf("%.1lf\n", (a[k- 1] + a[k]) / 2);
return 0;
}

Answer 1

while (scanf_s("%lf", &a[n++]) != EOF)改成

while ( n<N && scanf_s("%lf", &a[n++],1) != EOF)