为什么第二个是乱码的

Question

输入m个学生（最多为30人）n门课程（最多为5门）的成绩，然后计算并打印每个学生各门课的总分和平均分。其中，m和n的值由用户从键盘输入。
#include <stdio.h>
#define STUD 30 /* 最多可能的学生人数 /
#define COURSE 5 / 最多可能的考试科目数 */
void Total(int *pScore, int sum[], float aver[], int m, int n);
void Print(int *pScore, int sum[], float aver[], int m, int n);
int main()
{
int i, j, m, n, score[STUD][COURSE], sum[STUD];
float aver[STUD];
printf("How many students?");
scanf("%d", &m);
printf("How many courses?");
scanf("%d", &n);
printf("Input scores:\n");
for (i = 0; i < m; i++)
{
for (j = 0; j < n; j++)
{
scanf("%d", &score[i][j]);
}
}
Total(*score, sum, aver, m, n);
Print(*score, sum, aver, m, n);
return 0;
}
void Total(int *pScore, int sum[], float aver[], int m, int n)
{
int i, j;
for (i = 0; i < m; i++)
{
sum[i] = 0;
for (j = 0; j < n; j++)
{
sum[i] = sum[i] + pScore[i * n + j];
}
aver[i] = (float) sum[i] / n;
}
}
void Print(int *pScore, int sum[], float aver[], int m, int n)
{
int i;
printf("Result:\n");
for (i = 0; i < m; i++)
{
printf("%5d\t%6.1f\n", sum[i], aver[i]);
}
}

Answer 1

这行修改：sum[i] = sum[i] + pScore[i * COURSE + j];//sum[i] = sum[i] + pScore[i * n + j];修改

#include <stdio.h>
#define STUD 30 //最多可能的学生人数
#define COURSE 5 // 最多可能的考试科目数 
void Total(int* pScore, int sum[], float aver[], int m, int n);
void Print(int* pScore, int sum[], float aver[], int m, int n);
int main()
{
    int i, j, m, n, score[STUD][COURSE], sum[STUD];
    float aver[STUD];
    printf("How many students?");
    scanf("%d", &m);
    printf("How many courses?");
    scanf("%d", &n);
    printf("Input scores:\n");
    for (i = 0; i < m; i++)
    {
        for (j = 0; j < n; j++)
        {
            scanf("%d", &score[i][j]);
        }
    }
    Total(*score, sum, aver, m, n);
    Print(*score, sum, aver, m, n);
    return 0;
}
void Total(int* pScore, int sum[], float aver[], int m, int n)
{
    int i, j;
    for (i = 0; i < m; i++)
    {
        sum[i] = 0;
        for (j = 0; j < n; j++)
        {
            sum[i] = sum[i] + pScore[i * COURSE + j];
            //sum[i] = sum[i] + pScore[i * n + j];修改
        }
        aver[i] = (float)sum[i] / n;
    }
}
void Print(int* pScore, int sum[], float aver[], int m, int n)
{
    int i;
    printf("Result:\n");
    for (i = 0; i < m; i++)
    {
        printf("%5d\t%6.1f\n", sum[i], aver[i]);
    }
}