如何让结果在主函数输出

Question

求助如何用指针让结果（一个字符串中的字母，数字，空格，和其他字符）在主函数输出。

#include<stdio.h>
int main()
{  
    void count(char str[100]);
    char str[100];
    gets(str);
    count(str); 
}
void count(char str[100])
{
    int*l,*d,*s,*o;
    int letter=0,digit=0,space=0,other=0;
    int i;
    for(i=0;str[i]!=0;i++)
    {
    if((str[i]>'A'&&str[i]<'Z')||(str[i]>'a'&&str[i]<'z'))
        letter++;
    else if(str[i]>'0'&&str[i]<'9')
        digit++;
    else if(str[i]==32)
        space++;
    else other++;
    }
    l=&letter;
    d=&digit;
    s=&space;
    o=&other;
    printf("%d,%d,%d,%d",*l,*d,*s,*o);
}

Answer 1

// Q762150.cpp : This file contains the 'main' function. Program execution begins and ends there.
//

#include<stdio.h>
int main()
{
    void count(char str[100], int* l, int* d, int* s, int* o);
    char str[100];
    gets_s(str);
    int l, d, s, o;
    count(str, &l, &d, &s, &o);
    printf("%d,%d,%d,%d", l, d, s, o);
}
void count(char str[100], int *l, int *d, int *s, int *o)
{
    int letter = 0, digit = 0, space = 0, other = 0;
    int i;
    for (i = 0; str[i] != 0; i++)
    {
        if ((str[i] > 'A' && str[i] < 'Z') || (str[i] > 'a' && str[i] < 'z'))
            letter++;
        else if (str[i] > '0' && str[i] < '9')
            digit++;
        else if (str[i] == 32)
            space++;
        else other++;
    }
    *l = letter;
    *d = digit;
    *s = space;
    *o = other;
}