你好，请问代码运行结果不正确是什么问题呢

Question

/* 编写一个程序， 提示用户输入 3 组数， 每组数包含 5 个 double 类型的数（假
设用户都正确地响应， 不会输入非数值数据）。该程序应完成下列任务。
a.把用户输入的数据储存在 3×5 的数组中
b.计算每组(5 个)数据的平均值
c.计算所有数据的平均值
d.找出这 15 个数据中的最大值*/
#include<stdio.h>
int main()
{
int i,j;
//double a[5],b[5],c[5];
double alt[3][5];
double sum[3] = { 0,0,0 },sum_alt=0;
double aver[3],aver_alt;
//double aver_a, aver_b, aver_c, aver_alt;
printf("please input three groups number which have five numbers:\n");
for (i = 0; i < 3; i++)
{printf("the NO.%d group is:\n", i+1);
for(j=0;j<5;j++)
scanf_s("%lf", &alt[i][j]);
}//超过两行加括号
//alt[3][5] = a[1] + a[2] + a[3];
for (i = 0; i < 3; i++)
for (j = 0; j < 5; j++)
sum[i] = sum[i] + alt[i][j];
for (i = 0; i < 3; i++)
{
aver[i] = sum[i] / 3;
sum_alt = sum_alt + sum[i];
printf("the NO.%d average is %5.2lf\n", i+1, aver[i]);
}
aver_alt = sum_alt / 3;
printf("the altogher average is %5.2lf", aver_alt);//sum_alt / 3);
return 0;
}

Answer 1

（1）aver[i] = sum[i] / 3; 这里应该是除以5，不是除以3
（2）你没有求最大值。
（3）aver_alt = sum_alt / 3; //这里除以15，不是除以3
代码修改如下：

#include<stdio.h>
int main()
{
    int i,j;
    //double a[5],b[5],c[5];
    double alt[3][5];
    double sum[3] = { 0,0,0 },sum_alt=0;
    double aver[3],aver_alt;
    double maxv;
    //double aver_a, aver_b, aver_c, aver_alt;
    printf("please input three groups number which have five numbers:\n");
    for (i = 0; i < 3; i++)
    {
        printf("the NO.%d group is:\n", i+1);
        for(j=0;j<5;j++)
        {
            scanf_s("%lf", &alt[i][j]);
            //求最大值
            if(i==0 && j==0)
                maxv = alt[i][j];
            else
            {
                if(alt[i][j]>maxv)
                    maxv = alt[i][j];
            }
        }
    }//超过两行加括号
    //alt[3][5] = a[1] + a[2] + a[3];
    for (i = 0; i < 3; i++)
        for (j = 0; j < 5; j++)
            sum[i] = sum[i] + alt[i][j];
    for (i = 0; i < 3; i++)
    {
        aver[i] = sum[i] / 5; //这里是除以5
        sum_alt = sum_alt + sum[i];
        printf("the NO.%d average is %5.2lf\n", i+1, aver[i]);
    }
    aver_alt = sum_alt / 15; //这里除以15
    printf("the altogher average is %5.2lf\n", aver_alt);//sum_alt / 3);

    //显示最大值
    printf("max=%g\n",maxv);
    return 0;
}