//有两个磁盘文件A和B,各存放一行字母,今要求把这两个文件中的信息合并(按字母顺序排列),输出到一个新文件C中去。
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main()
{
FILE* fp;
errno_t err;
int i = 0, j;
char c[100], t, ch;
char str1[100], str2[100];
if (err = fopen_s(&fp, "test1", "w"))
{
printf("cannot open file\n");
exit(0);
}
printf("input a string:\n");
gets_s(str1);
while (str1[i] != '!')
{
if (str1[i] >= 'a' && str1[i] <= 'z')
str1[i] -= 32;
fputc(str1[i], fp);
i++;
}
//fputs(str, fp);
fclose(fp);
err = fopen_s(&fp, "test1", "r");
fgets(str1, strlen(str1) + 1, fp);
printf("%s\n", str1);
fclose(fp);
i = 0;
if (err = fopen_s(&fp, "test2", "w"))
{
printf("cannot open file\n");
exit(0);
}
printf("input a string:\n");
gets_s(str2);
while (str2[i] != '!')
{
if (str2[i] >= 'a' && str2[i] <= 'z')
str2[i] -= 32;
fputc(str2[i], fp);
i++;
}
//fputs(str, fp);
fclose(fp);
err = fopen_s(&fp, "test2", "r");
fgets(str2, strlen(str2) + 1, fp);
printf("%s\n", str2);
fclose(fp);
if (err = fopen_s(&fp, "test1", "r"))
{
printf("cannot open the file1!\n");
exit(0);
}
printf("file A:\n");
for (i = 0; (ch = fgetc(fp)) != EOF; i++)
{
c[i] = ch;
putchar(c[i]);
}
printf("\n");
fclose(fp);
if (err = fopen_s(&fp, "test2", "r"))
{
printf("cannot open the file2!\n");
exit(0);
}
printf("file B:\n");
for (;( ch = fgetc(fp))!=EOF; i++)
{
c[i] = ch;
putchar(c[i]);
}
printf("\n");
fclose(fp);
for(i=0;i<strlen(c);i++)
for (j = i + 1; j < strlen(c); j++)
{
if (c[i] > c[j])
{
t = c[i];
c[i] = c[j];
c[j] = t;
}
}
printf("file C:\n");
err = fopen_s(&fp, "text3", "w");
for (i = 0; i < strlen(c); i++)
{
fputc(c[i], fp);
putchar(c[i]);
}
printf("\n");
fclose(fp);
return 0;
}
为啥最后出现一串烫还有m?另外,原题是要求用上一题程序分别建立文件A和B,我这么写对吗?还是说建立AB要在另一个程序文件里写?求解