pyspider all时，出现TypeError

Question

命令行运行pyspider all时，出现报错
C:\Users\lenovo>pyspider all
f:\anaconda\lib\site-packages\pyspider\libs\utils.py:196: FutureWarning: timeout is not supported on your platform.
warnings.warn("timeout is not supported on your platform.", FutureWarning)
phantomjs fetcher running on port 25555

[I 220122 00:16:18 result_worker:49] result_worker starting...
[I 220122 00:16:19 processor:211] processor starting...
[I 220122 00:16:19 scheduler:647] scheduler starting...
[I 220122 00:16:19 scheduler:586] in 5m: new:0,success:0,retry:0,failed:0
[I 220122 00:16:19 tornado_fetcher:638] fetcher starting...
[I 220122 00:16:19 scheduler:782] scheduler.xmlrpc listening on 127.0.0.1:23333
[I 220122 00:16:19 run:420] phantomjs exited.
[I 220122 00:16:19 app:84] webui exiting...
[I 220122 00:16:19 tornado_fetcher:671] fetcher exiting...
[I 220122 00:16:19 scheduler:663] scheduler exiting...
[I 220122 00:16:19 result_worker:66] result_worker exiting...
[I 220122 00:16:20 processor:229] processor exiting...
Traceback (most recent call last):
  File "f:\anaconda\lib\runpy.py", line 193, in _run_module_as_main
    "__main__", mod_spec)
  File "f:\anaconda\lib\runpy.py", line 85, in _run_code
    exec(code, run_globals)
  File "F:\Anaconda\Scripts\pyspider.exe\__main__.py", line 7, in <module>
  File "f:\anaconda\lib\site-packages\pyspider\run.py", line 754, in main
    cli()
  File "f:\anaconda\lib\site-packages\click\core.py", line 829, in __call__
    return self.main(*args, **kwargs)
  File "f:\anaconda\lib\site-packages\click\core.py", line 782, in main
    rv = self.invoke(ctx)
  File "f:\anaconda\lib\site-packages\click\core.py", line 1236, in invoke
    return Command.invoke(self, ctx)
  File "f:\anaconda\lib\site-packages\click\core.py", line 1066, in invoke
    return ctx.invoke(self.callback, **ctx.params)
  File "f:\anaconda\lib\site-packages\click\core.py", line 610, in invoke
    return callback(*args, **kwargs)
  File "f:\anaconda\lib\site-packages\click\decorators.py", line 21, in new_func
    return f(get_current_context(), *args, **kwargs)
  File "f:\anaconda\lib\site-packages\pyspider\run.py", line 165, in cli
    ctx.invoke(all)
  File "f:\anaconda\lib\site-packages\click\core.py", line 610, in invoke
    return callback(*args, **kwargs)
  File "f:\anaconda\lib\site-packages\click\decorators.py", line 21, in new_func
    return f(get_current_context(), *args, **kwargs)
  File "f:\anaconda\lib\site-packages\pyspider\run.py", line 497, in all
    ctx.invoke(webui, **webui_config)
  File "f:\anaconda\lib\site-packages\click\core.py", line 610, in invoke
    return callback(*args, **kwargs)
  File "f:\anaconda\lib\site-packages\click\decorators.py", line 21, in new_func
    return f(get_current_context(), *args, **kwargs)
  File "f:\anaconda\lib\site-packages\pyspider\run.py", line 384, in webui
    app.run(host=host, port=port)
  File "f:\anaconda\lib\site-packages\pyspider\webui\app.py", line 59, in run
    from .webdav import dav_app
  File "f:\anaconda\lib\site-packages\pyspider\webui\webdav.py", line 207, in <module>
    '/': ScriptProvider(app)
TypeError: Can't instantiate abstract class ScriptProvider with abstract methods get_resource_inst

Answer 1

我尝试把webdav.py 18行from .app import app改为from app import app，把出问题的配置'provider_mapping': {'/': ScriptProvider(app) }注释掉，并且修改下面的'domaincontroller': NeedAuthController(app) 为'http_authenticator':{'HTTPAuthenticator':NeedAuthController(app),}居然就可以了。。虽然还不知道为啥，mark一下