asdliu1234 2022-01-30 07:06 采纳率: 50%
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已结题

想问一下大家,如何对word文档中AA-AA-F1-08定位,以及后六位十六进制数提取(例如02-A9-02-98-05-1C),不知道如何提取word中的字符串,

问题遇到的现象和发生背景

img

问题相关代码,请勿粘贴截图

代码

str1
['"(0x) AA', 'AA', 'F1', '08', '02', 'B0', '02', '9E', '04', '7C', '02', '6B', '8C" received']
str1[(str1.index(str2))+4:]
['02', '9E', '04', '7C', '02', '6B', '8C" received']
str1[(str1.index(str2))+4 : len(str1)-2]
['02', '9E', '04', '7C', '02']
str1[(str1.index(str2))+4 : len(str1)-1]
['02', '9E', '04', '7C', '02', '6B']

运行结果及报错内容
我的解答思路和尝试过的方法

A 19:32:20.128 "(0x) AA-AA-F1-08-02-A9-02-98-05-1C-02-69-1E" received
I 19:32:20.128 Notification received from 00001002-0000-1000-8000-00805f9b34fb, value: (0x) AA-AA-F1-08-02-A9-02-97-05-1B-02-69-1C
A 19:32:20.128 "(0x) AA-AA-F1-08-02-A9-02-97-05-1B-02-69-1C" received
I 19:32:20.187 Notification received from 00001002-0000-1000-8000-00805f9b34fb, value: (0x) AA-AA-F1-08-02-A8-02-96-05-1D-02-69-1C-AA-AA-F1-08-02-A9-02-97-05-1E-02-68-1E-AA-AA-F1-08-02-A9-02-98-05-21-02-6A-24-AA-AA-F1-08-02-A9-02-97-05-1F-02-68-1F-AA-AA-F1-08-02-AA-02-96-05-20-02-69-21-AA-AA-F1-08-02-A9-02-97-05-23-02-69-24-AA-AA-F1-08-02-A9-02-95-05-23-02-68-21
A 19:32:20.187 "(0x) AA-AA-F1-08-02-A8-02-96-05-1D-02-69-1C-AA-AA-F1-08-02-A9-02-97-05-1E-02-68-1E-AA-AA-F1-08-02-A9-02-98-05-21-02-6A-24-AA-AA-F1-08-02-A9-02-97-05-1F-02-68-1F-AA-AA-F1-08-02-AA-02-96-05-20-02-69-21-AA-AA-F1-08-02-A9-02-97-05-23-02-69-24-AA-AA-F1-08-02-A9-02-95-05-23-02-68-21" received
I 19:32:20.188 Notification received from 00001002-0000-1000-8000-00805f9b34fb, value: (0x) AA-AA-F1-08-02-A9-02-96-05-24-02-67-22
A 19:32:20.188 "(0x) AA-AA-F1-08-02-A9-02-96-05-24-02-67-22" received
I 19:32:20.189 Notification received from 00001002-0000-1000-8000-00805f9b34fb, value: (0x) AA-AA-F1-08-02-A9-02-99-05-27-02-69-2A

我想要达到的结果

['02', '9E', '04', '7C', '02', '6B

  • 写回答

1条回答 默认 最新

  • chuifengde 2022-01-30 09:59
    关注
    import docx
    import re
    
    doc = docx.Document("test.docx")
    con = doc.paragraphs[0].text
    
    res = re.findall('AA-AA-F1-08-(.*?)"', con, re.DOTALL)
    if res:
        for i in res:
            print(i[:17])
            
    '''--result
    02-A9-02-98-05-1C
    02-A9-02-97-05-1B
    02-A9-02-97-05-1B
    02-A8-02-96-05-1D
    02-A8-02-96-05-1D
    02-A9-02-96-05-24
    02-A9-02-96-05-24
    '''
    
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论 编辑记录

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问题事件

  • 系统已结题 2月7日
  • 已采纳回答 1月30日
  • 创建了问题 1月30日

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