后置递增运算符重置报错

Question

#include <iostream>
using namespace std;

class MyTeger{
    
public:

    friend ostream& operator<<(ostream &cout,MyTeger &p);
    MyTeger &operator++();
    MyTeger operator++(int);
            
private:
    int m_A;
    int m_B;
};

int main(){
    
    MyTeger p1;

    p1++;
    cout<<++p1;

这里前置++正确，但是后置++就报错，请问为什么呢？

    return 0;
} 

//左移运算符重载 
ostream& operator<<(ostream &cout,MyTeger &p){
    cout<<"m_A="<<p.m_A<<"  m_B="<<p.m_B<<endl;
    return cout;
}

//前置递增 
MyTeger &MyTeger:: operator++(){        
    m_A++;
    m_B++;
    return *this;
}

//后置递增 
MyTeger MyTeger::operator++(int){
    MyTeger temp=*this;
    m_A++;
    m_B++; 
    return temp;;
}

Answer 1

operator<<()第二个参数类型应改为const MyTeger&