c# 将字符串转为十六进制再赋值给字节数组

Question

如题：
将字符串“3YY09",转为十六进制后，赋值给字节数组

Answer 1

谢谢，这个可行

public static class HexStringConverter
{

    public static string StringToHex(this string hexString)
    {
        var sb = new StringBuilder();
        foreach (var t in hexString)
        {
            sb.Append(Convert.ToInt32(t).ToString("X")); 
        }
        return sb.ToString();
    }
    public static byte[] ToByteArray(this string hexString)
    {
        var numberChars = hexString.Length;
        var bytes = new byte[numberChars / 2];
        for (var i = 0; i < numberChars; i += 2)
        {
            bytes[i / 2] = Convert.ToByte(hexString.Substring(i, 2), 16);
        }
        return bytes;
    }
}