已知如下横纵坐标的坐标方程,怎么求位移?
x=rsin(2pint/60+A2sin(2pift+theta2))
y=vft+rcos(2pint/60+A2sin(2pif*t+theta2))
x=rsin(2pint/60+A2sin(2pift+theta2))
y=vft+rcos(2pint/60+A2sin(2pif*t+theta2))
位移的大小直接
x=r*sin(2*pi*n*t/60+A2*sin(2*pi*f*t+theta2))
y=v*f*t+r*cos(2*pi*n*t/60+A2*sin(2*pi*f*t+theta2))
u = sqrt(x^2+y^2)