java 使用dom3c解析xml文件问题，多级节点解析

Question

读取xml文件，
获取如下标签的NodeList，

NodeList impList = doc.getElementsByTagName("IMPLEMENTATION-DATA-TYPE");
for(int i = 0; i < impList.getLength(); i++) {
    Element impElement = (Element) impList.item(i); 
    NodeList impSubList = impElement.getElementsByTagName("IMPLEMENTATION-DATA-TYPE-ELEMENT");
    System.out.println("impSubList legth= " + impSubList.getLength());
    }

我想做到输出的impSubList legth=5，但是实际输出的长度是这个节点下所有的这个便签的长度。怎么一级一级解析下去 获取长度？

Answer 1

直接上代码

package cn.next;
import java.io.IOException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;
import org.w3c.dom.Text;

public class Test {
    public static void ReadTreeStructure(NodeList nodes) {

        for (int i = 0; i < nodes.getLength(); i++) {
            if (nodes.item(i).getNodeType() == Node.ELEMENT_NODE) {
                System.out.print(nodes.item(i).getNodeName() + " ");
                String value = ((Text) (nodes.item(i).getFirstChild())).getData().trim();
                if (value.getBytes().length != 0) {
                    System.out.print(value);
                }
                System.out.println();
            }

                        //如果节点还有子节点,递归调用
            if (nodes.item(i).getChildNodes().getLength() != 0) {
                ReadTreeStructure(nodes.item(i).getChildNodes());
            }
        }
    }

    public static void main(String[] args) {

        DocumentBuilderFactory docbf = DocumentBuilderFactory.newInstance();
        try {
            DocumentBuilder docb = docbf.newDocumentBuilder();
            Document doc = docb.parse("***.xml");
            NodeList nodes = doc.getElementsByTagName("IMPLEMENTATION-DATA-TYPE");
            ReadTreeStructure(nodes);
        } catch (ParserConfigurationException e) {
            e.printStackTrace();
        } catch (SAXException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

}