一个C语言编译错误问题

Question

#include<stdio.h>
int main(){
    char s[101];
    int sum=0;
    int u=0
    for(int i=0;s[i]!='\0';i++){
        scanf("%c",s[i]);
        u++;
    }
    for(int j=0;j<=i-1;j++){
        sum=sum+(s[i]-'\0');
    }
    int shuzi;
    for(int k=0;sum!=0;k++){
        shuzi=sum%10;
        sum=sum/10;
        if(shuzi==1){
            printf(" yi");
        }else if(shuzi==2){
            printf(" er");
        }else if(shuzi==3){
            printf(" san");
        }else if(shuzi==4){
            printf(" si");
        }else if(shuzi==5){
            printf(" wu");
        }else if(shuzi==6){
            printf(" liu");
        }else if(shuzi==7){
            printf(" qi");
        }else if(shuzi==8){
            printf(" ba");
        }else if(shuzi==9){
            printf(" jiu");
        }else if(shuzi==10){
            printf("shi");
        }

    } 
    return 0;
}

为什么会出现这个问题？

Answer 1

而且输入时还少了&;
改正如下：

  
#include<stdio.h>
int main(){
    char s[101];
    int sum=0;
    int u=0;
    int flag=0;
    for(int i=0;s[i]!='\0';i++){
        scanf("%c",&s[i]);
        u++;
        flag=i;
    }
    for(int j=0;j<=flag-1;j++){
        sum=sum+(s[flag]-'\0');
    }
    int shuzi;
    for(int k=0;sum!=0;k++){
        shuzi=sum%10;
        sum=sum/10;
        if(shuzi==1){
            printf(" yi");
        }else if(shuzi==2){
            printf(" er");
        }else if(shuzi==3){
            printf(" san");
        }else if(shuzi==4){
            printf(" si");
        }else if(shuzi==5){
            printf(" wu");
        }else if(shuzi==6){
            printf(" liu");
        }else if(shuzi==7){
            printf(" qi");
        }else if(shuzi==8){
            printf(" ba");
        }else if(shuzi==9){
            printf(" jiu");
        }else if(shuzi==10){
            printf("shi");
        }
 
    } 
    return 0;
}
 

测试图：

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