怎让符合条件1的运行了，才考虑条件2。如果没有条件1，则不运行条件2。不用threading，怎么实现？

Question

```python
import threading
import numpy as np
a = 3
while a < 10:

    list = np.random.randint(1,10,size=(5,2),dtype='int32')
    # list = [[2, 3], [1, 5],[5, 3], [3, 9]]
#
# 列表内部列表[0], 按照3,1的顺序输出 列表的[1]数值。比如 list = [[0,4],[1,2],[3,6] 列表[0]为3， 输出：6. 然后再和 列表[1]为3做运算。

# for i in range (len(list)):
    print(list)
    a += 8
    l1 = range(0,4)
    l2 = [1,]
    l3 = [3,]
    l4 = [1,3]


def ii():
    for i in range(1):
        if i  in list:
            print("l3_break2")
            # break
        else:
            for k in list:
                global Ti
                if k[0] == 3:
                        Ti = k[0] * k[1]
                        print("3:", k[1])
                        print("sum:", Ti)
                        break
def ii2():
    for i in range(1):
        if i in list:
            print("l2_break2")
            # break
        else:
            for k in list:
                if k[0] == 1:
                        J = k[0]
                        sum2 = np.array(J) + np.array(Ti)
                        print("1:", k[1])
                        print("sum2:", sum2)
                        break

if __name__ == '__main__':
    threading1 = threading.Thread(target=ii())
    threading2 = threading.Thread(target=ii2())
    threading1.start()
    threading1.join()
    threading2.start()
    threading2.join()

[[4 4]
[1 8]
[7 4]
[3 4]
[7 4]]
3: 4
sum: 12
1: 8
sum2: 13

Answer 1

第一种写法
if 条件1:
if 条件2:

第二种写法
if 条件1 and 条件2:
and相当于c和java里的&&，它有短路特性，如果条件1不符合，条件2的代码不会执行