eclipse里,if else语句换eclipse语句,求哥大带带
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- zcrazy胡说八道 2022-03-18 10:17关注
public class Number {
public static void main(String[] args) {
int number = 0,d1,d2,d3,d4,d5;
Scanner reader = new Scanner(System.in);
System.out.println("输入一个1-99999之间的数:");number = reader.nextInt(); d5 = number / 10000; d4 = (number % 10000) / 1000; d3 = (number % 1000) / 100; d2 = (number % 100) / 10; d1 = number % 10; int length = String.valueOf(Math.abs(number)).length(); switch (String.valueOf(number).length()){ case 1:{ switch (number){ case 0: System.out.printf("\n %d 不在1-99999之间",number); break; case 1: System.out.println(number + "是1位数"); System.out.println(number + "是回文数"); } break; } case 2:{ switch (length){ case 1: System.out.printf("\n %d 不在1-99999之间",number); break; case 2: System.out.println(number + "是2位数"); System.out.println((d2 == d1)?(number + "是回文数"):number + "不是回文数"); } break; } case 3:{ switch (length){ case 2: System.out.printf("\n %d 不在1-99999之间",number); break; case 3: System.out.println(number + "是3位数"); System.out.println((d3 == d1)?(number + "是回文数"):number + "不是回文数"); } break; } case 4:{ switch (length){ case 3: System.out.printf("\n %d 不在1-99999之间",number); break; case 4: System.out.println(number + "是4位数"); System.out.println((d4==d1&&d3==d2)?(number + "是回文数"):number + "不是回文数"); } break; } case 5:{ switch (length){ case 4: System.out.printf("\n %d 不在1-99999之间",number); break; case 5: System.out.println(number + "是5位数"); System.out.println((d5==d1&&d4==d2)?(number + "是回文数"):number + "不是回文数"); } break; } default:{ System.out.printf("\n %d 不在1-99999之间",number); } } }
}
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