求导，怎么求导 路程既要能对速度求导又能对时间求导

Question

求指教一下

怎么列一个既可以对时间求导又可以对速度求导的式子呀

Answer 1

那就直接

syms x1(t) x2(t)
y = x1 + x2 + 2*diff(x1);
dydt = diff(y,1)      % 对时间求导
dx1 = diff(x1);
dyddx1 = diff(y)/diff(dx1) % 对x1'求导

结果：

dydt(t) =
 
diff(x1(t), t) + diff(x2(t), t) + 2*diff(x1(t), t, t)
 
 
dyddx1(t) =
 
(diff(x1(t), t) + diff(x2(t), t) + 2*diff(x1(t), t, t))/diff(x1(t), t, t)
 

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