jsp中点击按钮报错内部服务器

Question

   public static String getenhm() throws IOException {
            List<String> commands = new ArrayList<>();
            commands.add("tshark");
            commands.add("-r");
            commands.add("F:\\test.pcapng");
            commands.add("-Y");
            commands.add("isakmp");
            commands.add("-T");
            commands.add("fields");
            commands.add("-e");
            commands.add("isakmp.ike.attr.encryption_algorithm");
            ProcessBuilder tshark = new ProcessBuilder(commands);
            Process process = tshark.start();
            String value1;
            BufferedReader bfReader1 = new BufferedReader(new InputStreamReader(process.getInputStream()));
            value1 = bfReader1.readLine();
            String[] shuzu1 = value1.split(",");
            System.out.println("加密算法的值为：" + value1);
            String hegui1;
            for (String s : shuzu1) {
                switch (s) {
                    case "1":

HTTP状态 500 - 内部服务器错误
类型 异常报告

消息 在 [138] 行处理 [/IPSec2.jsp] 时发生异常

描述 服务器遇到一个意外的情况，阻止它完成请求。

例外情况

org.apache.jasper.JasperException: 在 [138] 行处理 [/IPSec2.jsp] 时发生异常

135:             String value1;
136:             BufferedReader bfReader1 = new BufferedReader(new InputStreamReader(process.getInputStream()));
137:             value1 = bfReader1.readLine();
138:             String[] shuzu1 = value1.split("\\|");
139:             System.out.println("鍔犲瘑绠楁硶鐨勫�间负锛�" + value1);
140:             String hegui1;
141:             for (String s : shuzu1) {


Stacktrace:
    org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:605)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:498)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:383)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:331)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:764)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
根本原因。

java.lang.NullPointerException
    org.apache.jsp.IPSec2_jsp.getenhm(IPSec2_jsp.java:48)
    org.apache.jsp.IPSec2_jsp._jspService(IPSec2_jsp.java:428)
    org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:764)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:465)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:383)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:331)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:764)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
):注意 主要问题的全部 stack 信息可以在 server logs 里查看

请教为啥我在jsp中使用split()方法会报错啊，我想转换的是value1，但是我在页面上点击按钮提交却出现这个错误

Answer 1

IPSec2jsp文件的48行有空指针，检查调用split()方法的对象是否没有判空。