VSC++程序改正，要求一个程序可以输入出生日期到目标日期的天数

Question

#include
using namespace std;
int main()
{
cout << "请输入生日" << endl;
int y = 0;
int m = 0;
int d = 0;
int f = 0;
cin >> y, m, d;
cout << "请输入日期" << endl;
int y1, m1, d1 = 0;
cin >> y1 >> m1 >> d1;
//y,m,d是生日 y1，m1，d1是日期，day是最后输出的天数，a是中间年份天数，b是输入日期当年天数，c是输入生日当年天数,f是输入生日当年天数减去c

int a, b, c = 0;

for ( int y = y + 1; y < y1; y++)
{
    if (y%4==0&& y%100!=0||y%400 ==0)
    {
        a = a + 366;
    }
    else
    {
        a = a + 365;
    }

}

switch (m1)
{
case 12:
    b = 30 + b;
case 11:
    b = 31 + b;
case 10:
    b = 30 + b;
case 9:
    b = 31 + b;
case 8:
    b = 31 + b;
case 7:
    b = 30 + b;
case 6:
    b = 31 + b;
case 5:
    b = 30 + b;
case 4:
    b = 31 + b;
case 3:
    if (y1%4==0&&y1%100!=0||y1 %400 == 0)
    {
        b = 29 + b;
    }
    else
    {
        b = 30 + b;
    }
case 2:
    b = 31 + b;
case 1:
    b = b + d1;
}




switch (m)
{
case 12:
    c = 30 + c;
case 11:
    c = 31 + c;
case 10:
    c = 30 + c;
case 9:
    c = 31 + c;
case 8:
    c = 31 + c;
case 7:
    c = 30 + c;
case 6:
    c = 31 + c;
case 5:
    c = 30 + c;
case 4:
    c = 31 + c;
case 3:
    if (y%4==0&&y%100!=0||y%400==0)
    {
        c = 29 + c;
    }
    else
    {
        c = 28 + c;
    }
case 2:
    c = 31 + c;
case 1:
    c = c + d;
}

if (y%4==0&&y%100!=0||y%400==0)
{
    f = 366 - c;
}
else
{
    f = 365 - c;
}

cout << "二者相差天数为" << a + f + b << endl;

system("pause");

return 0;

}

Answer 1

出生年份的y在第一个for循环中被更改了，出生年的天数没有算进去。还有一些其他错误，稍后给你代码。
代码修改如下：

#include <iostream>
using namespace std;
int main()
{
    int days[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
    cout << "请输入生日" << endl;
    int y = 0;
    int m = 0;
    int d = 0;
    //int f = 0;
    int i;
    cin >> y>> m>> d;
    cout << "请输入日期" << endl;
    int y1, m1, d1 = 0;
    cin >> y1 >> m1 >> d1;
    //y,m,d是生日 y1，m1，d1是日期，day是最后输出的天数，a是中间年份天数，b是输入日期当年天数，c是输入生日当年天数,f是输入生日当年天数减去c

    int a, b, c = 0;

    //先计算当年的天数
    if(y < y1)
    {
        a = 0;
        if(y%4==0 && y%100!=0|| y%400==0)
            days[2] = 29;
        else
            days[2] = 28;
        for( i=m+1;i<=12;i++)
            a += days[i];
        a += days[m] - d;
        //然后计算年之间的天数
        b=0;
        for( i=y+1;i<y1;i++)
        {
            if(i%4==0 && i%100!=0|| i%400==0)
                b += 366;
            else
                b += 365;
        }
        //计算y1年的天数
        c = 0;
        if(y1%4==0 && y1%100!=0|| y1%400==0)
            days[2] = 29;
        else
            days[2] = 28;
        for( i=1;i<m1;i++)
        {
            c += days[i];
        }
        c += d1;
    }else if (y == y1) //同年
    {
        a = 0;
        b = 0;
        c = 0;
        if(m1 < m)
        {
            cout << "日期比生日早，输入错误";
            return 0;
        }else
        {
            if(m1==m)
                c = d1 - d;
            else
            {
                if(y%4==0 && y%100!=0|| y%400==0)
                    days[2] = 29;
                else
                    days[2] = 28;
                for( i = m+1;i<m1;i++)
                    b += days[i];
                b += days[m]- d;
                c = d1;
            }
        }
    }else
    {
        //y1<y，说明输入错误
        cout <<"日期比生日早，输入错误";
        return 0;
    }





    cout << "二者相差天数为" << a + b + c << endl;

    system("pause");

    return 0;
}

Answer 2

运行结果如下：

如有帮助，望采纳，谢谢。

Answer 3

请问printf是啥

Answer 4

day[2]=29又是什么